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(A) The fringe width $\beta$ for an interference pattern produced by a wedge of liquid is given by the formula: $\beta = \frac{\lambda}{2\mu	heta}$,w

Vedclass · Accepted Answer

by increasing the angle of the liquid wedge

Vedclass · Answer

(A) The fringe width $\beta$ for an interference pattern produced by a wedge of liquid is given by the formula: $\beta = \frac{\lambda}{2\mu	heta}$,where $\lambda$ is the wavelength of the light used,$\mu$ is the refractive index of the liquid,and $	heta$ is the angle of the wedge.From the formula,we can see that $\beta$ is inversely proportional to the angle of the wedge $	heta$ and the refractive index $\mu$ of the liquid.To decrease the fringe width $\beta$,we must increase the denominator of the expression.Therefore,increasing the angle of the liquid wedge $	heta$ will decrease the fringe width $\beta$.Thus,option $A$ is correct.

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